Question:A and B can do a piece of work in 12 days ; B and C can do it in 15 days ; A and C can do it in 20 days. In how many days will A, B and C finish it, working all together ?
Also, find the number of days taken by each to finish it working alone.
Answer (A + B)'s 1 day's work=112; (B + C)' s 1 day's work=115
and (A + C)'s 1 day's work=120
Adding, we get : 2 (A + B + C)'s 1 day's work
=(112+115+120)=15.
:. (A + B + C)' s 1 day's work=110
Thus A,B and C together can finish the work in 10 days.
Now A's 1 day's work
= [(A + B + C)'s 1 day's work] - [(B + C) 's 1 day's work]
=(110-115)=130
A alone can finish the work in 30 days.
Similarly, B's 1 day's work=(110-120)=120
:. B alone can finish the work in 20 days.
And C's 1 day's work