what would happen on trying to compile and run the following code..., Java, Java Technologies

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Question:What would happen on trying to compile and run the following code?class House {
 
 public final void MaintainMethod() {
  System.out.println("MaintainMethod");
 }
}

public class Building extends House {
 
 public static void main(String argv[]) {
  House h = new House();
  h.MaintainMethod();
 }
}

A A runtime error will occur because class House is not defined as final. 
B Successful compilation and output of "MaintainMethod" at run time. 
C A compilation error indicating that a class with any final methods must be declared final itself. 
D A compilation error indicating that you cannot inherit from a class with final methods.

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Question:What would happen on trying to compile and run the following code?class House { public final void MaintainMethod() { System.out.println("MaintainMethod"); } } public class Building extends House { public static void main(String argv[]) { House h = new House(); h.MaintainMethod(); } }

A A runtime error will occur because class House is not defined as final.

B Successful compilation and output of "MaintainMethod" at run time.

C A compilation error indicating that a class with any final methods must be declared final itself.

D A compilation error indicating that you cannot inherit from a class with final methods.

B

Question:What would happen on trying to compile and run the following code?
class House { public final void MaintainMethod() { System.out.println("MaintainMethod"); } } public class Building extends House { public static void main(String argv[]) { House h = new House(); h.MaintainMethod(); } }