Question:If A's height is 24% less than that of B, then how much percent is B's height more than that of A ?
Answer
Required percentage
= `{24/(100-24) xx 100}`%
= 31.57%.Question:If A's height is 24% less than that of B, then how much percent is B's height more than that of A ?
Required percentage
= `{24/(100-24) xx 100}`%
= 31.57%.Question:If the price of tea is increased by 20%, find by how much percent must a householder reduce her consumption of tea so as not to increase the expenditure ?
Reduction in Consumption
= `{ R/(100+R) xx 100}` %
=`(20/120 xx 100)` %
= `16 2/3` %.Question:If the price of sugar decreases by 20%,find by how much percent must a house holder increase her consumption of sugar so as not to decrease the expenditure ?
Increase in consumption
= `{R/(100-R xx 100)}` %
= `(20/80 xx 100)` %
= 25 %.Question:The population of a town is 176400. If it increases at the rate of 5% per annum, what will be its population 2 years hence ? What was it 2 years ago ?
Population after 2 years = `176400 xx (1 +5/100)^2` = `(176400 xx 21/20 xx 21/20)` = 194481. Population 2 years ago = `176400/(1 +5/100)^2` = `(176400 xx 20/21 xx 20/21)` = 160000.
Question:The value of a machine depreciates at the rate of 10% per annum. If its present value is Tk. 162000,What will be its worth after 2 years ?What was the value of the machine 2 years ago ?
Value of the machine after 2 years
= `Tk. [162000 xx (1 -10/100)^2]`
= `Tk.(162000 xx 9/10 xx 9/10)`
= Tk. 131220.
Value of the machine 2 years ago
= `Tk.{162000/(1 -10/100)^2}`
= `Tk (162000 xx 10/9 xx 10/9)`
= Tk. 200000.