Simple Interest, General Mathematics

Question:A man borrowed Rs 24000 from two money Ienders. For one loan, he paid 15% per annum and for the other 18% per annum. At the end of one year, he paid Rs. 4050. How much did he borrow at each rate ? 
AnswerLet the sum at 15% be Rs x and that at 18% be Rs (24000 - x).

`:. (x xx 15 xx 1)/(100) + ((24000 - x) xx 18 xx 1)/(100)`

`= 4050`

`or 15x + 432000 - 18x`

`= 405000 or x = 9000.`

:. Money borrowed at 18% = Rs. 15000.

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Question:What annual installment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest ? 
AnswerLet each installment be Rs. x. then

`(x + (x xx 12 xx 1)/(100)) + (x + (x xx 12 xx 2)/(100)) + x`

`= 1092`

`or (28x)/25 + (31x)/25 + x`

`= 1092 or (28x + 31x + 25x)`

`= (1092 xx 25)`

`or x = ((1092 xx 25)/(84))`

`= 325.`

:. Each installment = Rs. 325

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