Data types and variables, Adv C

Question: Which of the following is not modifier of data type in c?
A
extern

B
interrupt

C
huge

D
register

E
All are modifiers of data type

Note: na
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Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ double num=5.2; int var=5; printf(\"%d\\t\",sizeof(!num)); printf(\"%d\\t\",sizeof(var=15/2)); printf(\"%d\",var); return 0; }
A
4 2 7

B
4 4 5

C
2 2 5

D
2 4 7

E
8 2 7

Note: sizeof(Expr) operator always returns the an integer value which represents the size of the final value of the expression expr. Consider on the following expression: !num =!5.2 =0 0 is int type integer constant and it size is 2 by in TURBO C 3.0 compiler and 4 in the TURBO C 4.5 and Linux GCC compilers. Consider on the following expression: var = 15/2 => var = 7 => 7 7 is int type integer constant. Any expression which is evaluated inside the sizeof operator its scope always will be within the sizeof operator. So value of variable var will remain 5 in the printf statement.
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Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ const int *p; int a=10; p=&a; printf("%d",*p); return 0; }
A
0

B
10

C
Garbage value

D
Any memory address

E
Error: Cannot modify const object

Note: In the following declaration const int *p; p can keep address of constant integer.
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Question: Consider on following declaration: (i)short i=10; (ii) static i=10; (iii) unsigned i=10; (iv) const i=10; Choose correct one:
A
Only (iv) is incorrect

B
Only (ii) and (iv) are incorrect

C
Only (ii),(iii) and (iv) are correct

D
Only (iii) is correct

E
All are correct declaration

Note: Default data type of above all declaration is int.
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Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ int a= sizeof(signed) +sizeof(unsigned); int b=sizeof(const)+sizeof(volatile); printf("%d",a+++b); return 0; }
A
10

B
9

C
8

D
Error: Cannot find size of modifiers

E
Error: Undefined operator +++

Note: Default data type of signed, unsigned, const and volatile is int. In turbo c 3.0 size of int is two byte. So, a = 4 and b =4 Now, a+++b = a++ + b = 4 + 4 //due to post increment operator. =8 Note: In turbo c 4.5 and Linux gcc compiler size of int is 4 byte so your out will be 16
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Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ int a= sizeof(signed) +sizeof(unsigned); int b=sizeof(const)+sizeof(volatile); printf("%d",a+++b); return 0; }
A
10

B
9

C
8

D
Error: Cannot find size of modifiers

E
Error: Undefined operator +++

Note: Turbo C++ 3.0: 8 Turbo C ++4.5: 8 Linux GCC: 16 Visual C++: 16 Default data type of signed, unsigned, const and volatile is int. In turbo c 3.0 size of int is two byte. So, a = 4 and b =4 Now, a+++b = a++ + b = 4 + 4 //due to post increment operator. =8 Note: In turbo c 4.5 and Linux gcc compiler size of int is 4 byte so your out will be 16
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Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ signed x,a; unsigned y,b; a=(signed)10u; b=(unsigned)-10; y = (signed)10u + (unsigned)-10; x = y; printf("%d %u\t",a,b); if(x==y) printf("%d %d",x,y); else if(x!=y) printf("%u %u",x,y); return 0; }
A
10 -10 0 0

B
10 -10 65516 -10

C
10 -10 10 -10

D
10 65526 0 0

E
Compilation error

Note: Turbo C++ 3.0: 10 65526 0 0 Turbo C ++4.5: 10 65526 0 0 Linux GCC: 10 4294967286 0 0 Visual C++: 10 4294967286 0 0 a=(signed)10u; signed value of 10u is +10 so, a=10 b=(unsigned)-10; unsigned value of -10 is : MAX_VALUE_OF_UNSIGNED_INT – 10 + 1 In turbo c 3.0 complier max value of unsigned int is 65535 So, b = 65526 y = (signed)10u + (unsigned)-10; = 10 + 65526 = 65536 = 0 (Since 65536 is beyond the range of unsigned int. zero is its corresponding cyclic vlaue) X = y = 0
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Question: Which of the following is integral data type?
A
void

B
char

C
float

D
double

E
None of these

Note: In c char is integral data type. It stores the ASCII value of any character constant.
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Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ volatile int a=11; printf("%d",a); return 0; }
A
11

B
Garbage

C
-2

D
We cannot predict

E
Compilation error

Note: We cannot predict the value of volatile variable because its value can be changed by any microprocessor interrupt.
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Question: What is the range of signed int data type in that compiler in which size of int is two byte?
A
-255 to 255

B
-32767 to 32767

C
-32768 to 32768

D
-32767 to 32768

E
-32768 to 32767

Note: Note: Size of int is always equal to word length of micro preprocessor in which your compiler has based.
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Question: Which of the following is not modifier of data type in c?

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ double num=5.2; int var=5; printf(\"%d\\t\",sizeof(!num)); printf(\"%d\\t\",sizeof(var=15/2)); printf(\"%d\",var); return 0; }

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ const int p; int a=10; p=&a; printf("%d",p); return 0; }

Question: Consider on following declaration: (i)short i=10; (ii) static i=10; (iii) unsigned i=10; (iv) const i=10; Choose correct one:

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ int a= sizeof(signed) +sizeof(unsigned); int b=sizeof(const)+sizeof(volatile); printf("%d",a+++b); return 0; }

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ int a= sizeof(signed) +sizeof(unsigned); int b=sizeof(const)+sizeof(volatile); printf("%d",a+++b); return 0; }

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ signed x,a; unsigned y,b; a=(signed)10u; b=(unsigned)-10; y = (signed)10u + (unsigned)-10; x = y; printf("%d %u\t",a,b); if(x==y) printf("%d %d",x,y); else if(x!=y) printf("%u %u",x,y); return 0; }

Question: Which of the following is integral data type?

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ volatile int a=11; printf("%d",a); return 0; }

Question: What is the range of signed int data type in that compiler in which size of int is two byte?

Question: Which of the following is not modifier of data type in c?

Question: What will be output when you will execute following c code?#include<stdio.h> int main(){ double num=5.2; int var=5; printf(\"%d\\t\",sizeof(!num)); printf(\"%d\\t\",sizeof(var=15/2)); printf(\"%d\",var); return 0; }

Question: What will be output when you will execute following c code?#include<stdio.h> int main(){ const int *p; int a=10; p=&a; printf("%d",*p); return 0; }

Question: Consider on following declaration: (i)short i=10; (ii) static i=10; (iii) unsigned i=10; (iv) const i=10; Choose correct one:

Question: What will be output when you will execute following c code?#include<stdio.h> int main(){ int a= sizeof(signed) +sizeof(unsigned); int b=sizeof(const)+sizeof(volatile); printf("%d",a+++b); return 0; }

Question: What will be output when you will execute following c code?#include<stdio.h> int main(){ int a= sizeof(signed) +sizeof(unsigned); int b=sizeof(const)+sizeof(volatile); printf("%d",a+++b); return 0; }

Question: What will be output when you will execute following c code?#include<stdio.h> int main(){ signed x,a; unsigned y,b; a=(signed)10u; b=(unsigned)-10; y = (signed)10u + (unsigned)-10; x = y; printf("%d %u\t",a,b); if(x==y) printf("%d %d",x,y); else if(x!=y) printf("%u %u",x,y); return 0; }

Question: Which of the following is integral data type?

Question: What will be output when you will execute following c code?#include<stdio.h> int main(){ volatile int a=11; printf("%d",a); return 0; }

Question: What is the range of signed int data type in that compiler in which size of int is two byte?

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ double num=5.2; int var=5; printf(\"%d\\t\",sizeof(!num)); printf(\"%d\\t\",sizeof(var=15/2)); printf(\"%d\",var); return 0; }

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ const int p; int a=10; p=&a; printf("%d",p); return 0; }

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ int a= sizeof(signed) +sizeof(unsigned); int b=sizeof(const)+sizeof(volatile); printf("%d",a+++b); return 0; }

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ int a= sizeof(signed) +sizeof(unsigned); int b=sizeof(const)+sizeof(volatile); printf("%d",a+++b); return 0; }

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ signed x,a; unsigned y,b; a=(signed)10u; b=(unsigned)-10; y = (signed)10u + (unsigned)-10; x = y; printf("%d %u\t",a,b); if(x==y) printf("%d %d",x,y); else if(x!=y) printf("%u %u",x,y); return 0; }

Question: What will be output when you will execute following c code?
#include<stdio.h> int main(){ volatile int a=11; printf("%d",a); return 0; }