Question: How will you count the odd numbers from the array shown below using LINQ in .Net framework 4.0? int[]numbers={5,4,1,3,9,8,6,7,2,0};
A
B
C
D
int findoddNumbers = numbers.Count(n => n % 2 == 1);
B
int findoddNumbers = numbers.Count( n % 2 == 1);
C
int findoddNumbers = (from number in numbers where numbers%2==1 select Count());
D
int findoddNumbers = (from number in numbers where number%2==1 select numbers).Count();
Note: Not available