Question:What is the greatest number of three digits which when divided by 6, 9 and 12 leaves a remainder of 3 in each case ?
A 975
B 996
C 939
D 903
/49
+ Answer
A
+ Explanationsolution:
Greatest number of 3 digits is 999.
L.C.M. of 6,9and12=36.
On dividing 999 by 36, remainder obtained is 27.
∴ Greatest number of 3 digits divisible by 6,9,12=(999-27)=972.
∴ Required number = (972+30)=975.