the height and the radius of base a cone are each increased..., Area & Volume, General Mathematics

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Question:The height and the radius of the base of a cone are each increased by  $100%$ . The volume of the new cone becomes how many times of the volume of the original cone ?

A  $8 times$  
B  $6 times$  
C  $4 times$  
D  $3 times$

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+ AnswerA

+ ExplanationLet radius = r & height = h Then, volume $=1/3 π r^2 h.$ 

New radius $= 200/100 r = 2r$  and new height 

 $= 200/100 h = 2h.$ 

:. New volume 

 $= 1/3 π xx (2r)^2 xx 2h$ 

 $= 8 xx 1/3 π r^2 h$ 

 $= 8 xx$ (original volume)

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Question:The height and the radius of the base of a cone are each increased by 100%100%. The volume of the new cone becomes how many times of the volume of the original cone ?

A 8×8 times

B 6×6 times

C 4×4 times

D 3×3 times

A

Question:The height and the radius of the base of a cone are each increased by $100%$ . The volume of the new cone becomes how many times of the volume of the original cone ?

A $8 times$

B $6 times$

C $4 times$

D $3 times$