Question:`p(1^2+2^2+3^2''''''+n^2)=1+2+3+......+n` হ p =?লে
A 3 B `2n+1` C `(2n+1)/3` D `3/(2n+1)`
+ AnswerD
+ Explanation`p=1+2+3+.....n/`1^2+2^2+3^2.......+n^2= n(n+1)/2/n(n+1)(2n+1)/6
+ Report