1. Question:In a game of 80 points, A can give B 5 points and C 15 points. Then how many points B can give C in a game 60 ? 

    Answer
    A : B = 80 : 75, A : C = 80 : 65
    
    `B/C = (B/A xx A/C)`
    
    `= (75/80 xx 80/65)`
    
    `= 15/13 = 60/52 = 60 : 52`
    
    :. In a game of 60, B can give C 8 points.






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  2. Question:Find the day of the week on 6th July, 1776. 

    Answer
    (i) 16th july, 1776 means 
    
        = (1775 years + period from 1st January to 16th July)
    
    Now, 1600 years have 0 odd day.
    
    100 years = (18 leap years + 57 ordinary years)
    
                  = (36 + 57) odd days = 93 odd days
    
                 = (13 weeks + 2 days) of odd days 
    
                 = 2 odd days.
    
    :. 1775 years have (0 + 5 + 2) odd days i,e 0 odd days.
    
    Now, days from 1st Jan, 16th July ; 1776 
    
    Jan         Feb     March      April       May     June    July
    
    31    +    29   +  31     +   30    +  31    +   30    +  16   = 198 days
    
      = (28 weeks + 2 days) = 2 odd days.
    
    :. Total number of odd days = (0 + 2) = 2.
    
    :. The day of the week was ' Tuesday'






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  3. Question:What was the day of the week on 12th January, 1979 ? 

    Answer
    Number of odd days in (1600 + 300) years = (0 + 1) = 1.
    
    78 years = (19 leap years + 59 ordinary years)
    
            = (38 + 59) odd days = 97 odd days = 6 odd days.
    
        12 days of January have 5 odd days.
    
    :. Total number of odd days = (1 + 6 + 5) = 5 odd days.
    
    :. The desired day was 'Friday'.






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  4. Question:Find the day of the week on 25th December, 1995. 

    Answer
    1600 years have 0 odd day.
    
    300 years have 1 odd day.
    
    94 years = (23 leap years + 71 ordinary years)
    
    = (46 + 71) odd days = 117 odd days = 5 odd days.
    
    Number of days from 1st Jan, 1995 to 25 th Dec, 1995 = 359 days.
    
     = (51 weeks + 2 days) = 2 odd days.
    
    :. Total number of odd days = (0 + 1 + 5 + 2) odd days = 1 odd day.
    
    :. Required day is 'Monday'.






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  5. Question:On what dates of October, 1994 did Monday fall ? 

    Answer
    Find the day on 1st October, 1994.
    
    1600 years contain 0 odd day.
    
    300 years contain 1 odd day.
    
    93 years = (23 leap years + 70 ordinary years) 
    
    = (46 + 70) odd years = 116 odd days = 4 odd days.
    
    Days from 1st Jan, 1994 to 1st Oct, 1994
    
    Jan    Feb    March     April    May     June    July    Aug    Sept        Oct
    
    31 +   28  +   31    +   30  +  31  +  30   +  31  +  31  +  30   +    1
    
    = 274  days = 39 weeks + 1 days = 1 odd day.
    
    :. Total number of odd days = (0 + 1 + 4 + 1) = 6.
    
    :.  1st Oct, 1994 was 'Saturday'
    
    :. Monday fell on 3rd October, 1994.
    
    During October 1994, Monday fell on 3rd, 17th and 24 th.






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