1. Question:The population of a town is 176400. If it increases at the rate of 5% per annum, what will be its population 2 years hence ? What was it 2 years ago ? 

    Answer
    Population after 2 years
    
     = `176400 xx (1 +5/100)^2`
    
     = `(176400 xx 21/20 xx 21/20)` 
    
     = 194481.
    
     Population 2 years ago 
    
     = `176400/(1 +5/100)^2` 
    
     = `(176400 xx 20/21 xx 20/21)`
    
     = 160000.






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  2. Question:The value of a machine depreciates at the rate of 10% per annum. If its present value is Tk. 162000,What will be its worth after 2 years ?What was the value of the machine 2 years ago ? 

    Answer
    Value of the machine after 2 years  
    
     = `Tk. [162000 xx (1 -10/100)^2]`
    
     = `Tk.(162000 xx 9/10 xx 9/10)` 
    
     = Tk. 131220.
    
     Value of the machine 2 years ago 
    
     = `Tk.{162000/(1 -10/100)^2}` 
    
     = `Tk (162000 xx 10/9 xx 10/9)` 
    
     = Tk. 200000.






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  3. Question:A man buys an article for tk 27.50 and sells it for tk 28.60. find his gain percent. 

    Answer
    4%






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  4. Question:If a ratio is purchased for tk 27.50 and sells it for tk 28.60. Find his gain percent. 

    Answer
    C.P = Tk 450
    
     S.P = Tk 465.50
    
     Loss =Tk`(490-465.50)` 
    
     = Tk 24.50
    
     :. Loss % = `((24.50)/490xx 100)` %
    
      = 5%






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  5. Question:By selling a book for tk 115.20, a man loses 10%. At what price should he sell it to gain 5%? 

    Answer
    Let the new S.P be Tk x
    
     (100-Loss%) : (1st S.P) = (100 + gain%): (2nd S.P)
    
     or, `(100-10)/115.20` = `(100+5)/x`
    
     or, x = `(105 xx 115.20/90)` = 134.40 
    
     `:.` New S.P = Tk 134.40






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