Question: A and B working separately can do a piece of work in 9 and 12 days respectively. If they work for a day alternately, A beginning, in how many days the work will be completed ?
A
B
C
D
1012
B
1013
C
1014
D
1023
Note: solution:
(A+B)′s2 day's work =(19+112)
=736.
Work done in 5 pairs of days =(5×736)
=3536.
Remaining work =(1-3536)
=136.
On 11th day, it is A's turn.
19 work is done by him in 1 day.
136 work id done by him in (9×136)
=14day.
∴Total time taken =1014 days.